Addition - Examples, Exercises and Solutions

To find the resulting number when ten units are added to 72, we will perform the following steps:

• Step 1: Identify the starting number, which is 72.
• Step 2: Add 10 to the starting number. This is done by calculating $72 + 10$.

Let's perform the calculation:

$72 + 10 = 82$

Therefore, the resulting number when ten units are added to 72 is $82$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the initial number and the amount to be added.
• Step 2: Perform the addition of the two numbers.

Now, let's work through each step:

Step 1: The initial number is given as 66, and we need to add 20 to it.

Step 2: We'll perform the addition:
$66 + 20 = 86$

Therefore, the solution to the problem is $86$.

To solve this problem, we'll perform simple addition:
Step 1: Identify the numbers to be added, which are 31 and 50.
Step 2: Calculate the sum: $31 + 50$.

Let's perform the calculation:

• Start the addition from the rightmost digit (units place).
• In the units place, add 1 (from 31) and 0 (from 50), giving us 1.
• In the tens place, add 3 (from 31) and 5 (from 50), which gives us 8.

Since there's nothing to carry over, the sum directly gives us the resulting number. Thus, $31 + 50 = 81$.

Therefore, the resulting number when adding fifty units to the number 31 is $81$.

To solve the problem, we will perform simple addition:

• Step 1: Identify the numbers involved. We have the number $44$ and we need to add $30$ to it.
• Step 2: Use the addition formula to find the sum. This is calculated as $44 + 30$.
• Step 3: Perform the calculation. Since $44 + 30 = 74$, we find that the resulting number is $74$.

Therefore, the solution to the problem is $74$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the initial number.
• Step 2: Add 3 tens to the initial number.
• Step 3: Add 4 units to the result of Step 2.

Now, let's work through each step:
Step 1: The problem gives us the initial number as $61$.
Step 2: Add 3 tens (which is $30$) to $61$:
$61 + 30 = 91$.
Step 3: Add 4 units to $91$:
$91 + 4 = 95$.

Therefore, the resulting number after adding 3 tens and 4 units to $61$ is $95$.

To solve this problem, we'll follow these steps:

• Step 1: Calculate the value of 6 tens.
• Step 2: Calculate the value of 7 units.
• Step 3: Add the values obtained in Steps 1 and 2.
• Step 4: Add this result to the initial number.

Let's work through each step:

Step 1: Calculate the value of 6 tens.
Each "ten" represents 10 units, so 6 tens equals $6 \times 10 = 60$.

Step 2: Calculate the value of 7 units.
Each "unit" represents 1, so 7 units equal $7 \times 1 = 7$.

Step 3: Add the values from Steps 1 and 2.
The total value of tens and units is $60 + 7 = 67$.

Step 4: Add this result to the initial number, 12.
So, $12 + 67 = 79$.

Therefore, when we add 6 tens and 7 units to the number 12, we obtain $79$.

To solve this problem, we need to add one ten (10) and one unit (1) to the number 66.

We'll follow these steps to find the new number:

• Step 1: Start with the original number, $66$.
• Step 2: Add one ten. This means adding $10$ to $66$.
  $66 + 10 = 76$.
• Step 3: Add one unit to the result from Step 2. This means adding $1$ to $76$.
  $76 + 1 = 77$.

Therefore, after adding one ten and one unit to 66, the resulting number is $77$.

To solve this problem, we'll follow these steps:

• Step 1: Add the 3 tens to the number 55.
• Step 2: Add the 4 units to the result from Step 1.

Let's work through each step:

Step 1: We need to add three tens to 55. Three tens equal $3 \times 10 = 30$.
Thus, adding 30 to 55 gives us:

$55 + 30 = 85$

Step 2: Now, we add the 4 units to the result of Step 1 (which is 85).
Adding 4 gives us:

$85 + 4 = 89$

Therefore, the solution to the problem is $89$.

To solve this problem, we'll perform the addition step-by-step, carefully keeping track of place values.

First, we start with the number 34.
We need to add 2 tens, which is equivalent to adding 20. Thus:
$34 + 20 = 54$

Next, add 2 units to the new total:
$54 + 2 = 56$

The final number we get after adding 2 tens and 2 units to 34 is $\mathbf{56}$.

Let's solve this problem step by step.

Step 1: Identify the numbers to be added:
We have $55$ and $40$.

Step 2: Perform the addition:
- Align the numbers according to their place values:
    $55$
+ $40$
-----------
- Add the digits in the ones place: $5 + 0 = 5$
- Add the digits in the tens place: $5 + 4 = 9$
Thus, combining these, the sum is $95$.

Therefore, the solution to the problem $55 + 40$ is $95$.

To solve this problem, we'll follow these steps:

• Step 1: Identify the numbers to add, which are $10$ and $34$.

• Step 2: Perform the addition of these numbers.

Now, let's work through these steps:

Step 1: We have the numbers $10$ and $34$ to be added.

Step 2: Align the numbers vertically as follows:

$\begin{array}{c} 10 \\ +34~~~ \\ \hline \end{array}$

Start adding from the rightmost digits:
$0 + 4 = 4$
In this case, there is no carry-over.
Now add the next column on the left:
$1 + 3 = 4$

Therefore, the final sum is $44$.

Step 3: Ensure that $44$ matches the provided answer choice. Indeed, option 4 corresponds to our calculation.

Therefore, the solution to the problem is $44$.

To solve the addition problem $22 + 36$, we will follow these steps:

• Step 1: Align the numbers vertically based on place value:

  22
+36
----

Step 2: Begin adding from the rightmost column, which is the units place:

Units: $2 + 6 = 8$. Write 8 under the line in the units place.

Step 3: Move to the tens column:

Tens: $2 + 3 = 5$. Write 5 under the line in the tens place.

At this point, we have summed the digits in each column and written the final result below the other numbers.

  22
+36
----
  58

Therefore, the sum of 22 and 36 is $\mathbf{58}$.

The correct answer is

$58$

.

Let's solve this problem using basic addition:

• Step 1: Write down the numbers 35 and 22 with the units and tens places aligned:

 35
+22
----

• Step 2: Start by adding the units place digits: $5 + 2 = 7$.
• Step 3: Add the tens place digits: $3 + 2 = 5$.

Combine the results to get the final sum:

 35
+22
----
 57

Therefore, the solution to the problem is $57$, which corresponds to choice 2.

To solve the addition problem $43 + 51$, we'll follow these steps:

• Step 1: Align the numbers vertically by their place value (units, tens).
• Step 2: Start adding from the rightmost column, which is the units column, and proceed to the leftmost column (tens).

Let's perform the addition:
Step 1: Align the numbers:
    43
+  51
------

Step 2: Add the units column: $3 + 1 = 4$. Write 4 in the units place.
Add the tens column: $4 + 5 = 9$. Write 9 in the tens place.

Thus, the sum of 43 and 51 is $94$.

The correct answer is $94$, which corresponds to choice 1.

To solve this problem, we'll follow these steps:

• Step 1: Calculate the total capacity of the paddocks.
• Step 2: Subtract the total paddock capacity from the total number of horses.

Let's proceed with each step:

Step 1: Calculate the total capacity of the paddocks.
Each paddock can hold 10 horses. There are 3 paddocks, so the total capacity is:

$3 \times 10 = 30$

Step 2: Subtract the total paddock capacity from the total number of horses.
We start with 47 horses. Placing 30 horses in the paddocks leaves:

$47 - 30 = 17$

Therefore, the number of horses that will remain in the field is $17$.