Square Roots: Solving the problem

$\sqrt{441}=$

The root of 441 is 21.

$21\times21=$

$21\times20+21=$

$420+21=441$

$21$

$(\sqrt{380.25}-\frac{1}{2})^2-11=$

According to the order of operations, we'll first solve the expression in parentheses:

$(\sqrt{380.25}-\frac{1}{2})=(19.5-\frac{1}{2})=(19)$

In the next step, we'll solve the exponentiation, and finally subtract:

$(19)^2-11=(19\times19)-11=361-11=350$

350

$\sqrt{64}=$

8

$\sqrt{36}=$

6

$5+\sqrt{36}-1=$

$10$

$\sqrt{0.25}=$

0.5

$81+\sqrt{81}+10=$

$100$

$143-\sqrt{121}+18=$

$150$

$\sqrt{272\frac{1}{4}}=$

$16\frac{1}{2}$

$4\times\sqrt{0.49}+4^2=$

18.8

$\sqrt{225}-15=$

0

$\sqrt{961}-\sqrt{1}=$

30

$\sqrt{49}+\sqrt{36}=$

13

$\sqrt{144}+12=$

24

$\sqrt{400}-\sqrt{225}=$

5

$\sqrt{16}+\sqrt{4}=$

$6$