Algebraic Solution: Solve using the substitution method

Solve the following equations:

$\begin{cases} 2x+y=9 \\ x=5 \end{cases}$

$x=5,y=-1$

Solve the following equations:

$\begin{cases} x+y=18 \\ y=13 \end{cases}$

$x=5,y=13$

Find the value of x and and band the substitution method.

$\begin{cases} -x-2y=4 \\ 3x+y=8 \end{cases}$

$x=4,y=-4$

Find the value of x and and band the substitution method.

$\begin{cases} x+y=5 \\ 2x-3y=-15 \end{cases}$

$x=0,y=5$

Find the value of x and and band the substitution method.

$\begin{cases} -5x+9y=18 \\ x+8y=16 \end{cases}$

$x=0,y=2$

Find the value of x and and band the substitution method.

$(I)-x+3and=12$

$(II)4x+2and=10$

$x=\frac{3}{7},y=\frac{29}{7}$

Choose the correct answer for the following exercise:

$\begin{cases} x+y=15 \\ 2x+2y=12\frac{}{} \end{cases}$

No solution

Find the value of x and and band the substitution method.

$\begin{cases} -5x+y=8 \\ 3x-2y=11 \end{cases}$

$x=-\frac{27}{7},y=-\frac{79}{7}$

Find the value of x and and band the substitution method.

$\begin{cases} -4x+4y=15 \\ 2x+8y=12 \end{cases}$

$x=-\frac{9}{5},y=\frac{39}{20}$

Choose the correct answer for the following exercise:

$\begin{cases} -2x+3y=14 \\ -4x+6y=28 \end{cases}$

Infinite solutions

Find the value of x and and band the substitution method.

$\begin{cases} x+4y=5-3y \\ 2x+3y=6 \end{cases}$

$x=\frac{27}{11},y=\frac{4}{11}$

Find the value of x and and band the substitution method.

$\begin{cases} 8x-2y=10 \\ 3x+3y=9 \end{cases}$

$x=\frac{8}{5},y=\frac{14}{10}$

Choose the correct answer for the following exercise:

$\begin{cases} -8x+5y=10 \\ -24x+15y=30 \end{cases}$

Infinite solutions

Choose the correct answer for the following exercise:

$\begin{cases} 3x-4y=10 \\ 9x-12y=15 \end{cases}$

No solution

Solve the following equations for x and y using the substitution method:

$\begin{cases} \frac{2x-y}{2}+\frac{-3y+x}{5}=7 \\ \frac{-y-x}{8}-\frac{5y+x}{6}=4 \end{cases}$

$x=1.57,y=-4.65$

Look at the two equations below. Calculate the values of x and y using the substitution method.

$\begin{cases}\frac{x-y}{2}+\frac{-y+x}{3}=-6 \\ \frac{-y-x}{5}-\frac{y+x}{1}=8\end{cases}$

$x=-6.933,y=0.266$

Choose the correct answer for the following exercise:

$\begin{cases} -8x+5y=2 \\ -16x+10y=5 \end{cases}$

No solution

Solve the following equations for x and y using the substitution method:

$\begin{cases} \frac{2x-3y}{4}+\frac{x-y}{5}=30 \\ \frac{2y+x}{8}-\frac{3y-x}{4}=12 \end{cases}$

$x=-576,y=-456$

Solve the following equations for x and y using the substitution method.

$\begin{cases} \frac{3x-2y}{8}+\frac{x-y}{2}=14 \\ \frac{4x+3y}{5}-\frac{2x-2y}{3}=20 \end{cases}$

$x=27.08,y=12.93$

Solve the following equations for x and y using the substitution method.

$\begin{cases} \frac{-x+3y}{6}+\frac{5x-y}{3}=12 \\ \frac{2x-4y}{10}-\frac{-2x-2y}{5}=15 \end{cases}$

$x=25,y=-153$