Algebraic Solution: Solve using the substitution method

Solve the following equations:

$(I)2x+y=9$

$(II)x=5$

$x=5,y=-1$

Solve the following equations:

$(I)x+y=18$

$(II)y=13$

$x=5,y=13$

Find the value of x and and band the substitution method.

$(I)-x-2and=4$

$(II)3x+and=8$

$x=4,y=-4$

Find the value of x and and band the substitution method.

$(I)x+and=5$

$(II)2x-3and=-15$

$x=0,y=5$

Find the value of x and and band the substitution method.

$(I)-5x+9and=18$

$(II)x+8and=16$

$x=0,y=2$

Find the value of x and and band the substitution method.

$(I)-x+3and=12$

$(II)4x+2and=10$

$x=\frac{3}{7},y=\frac{29}{7}$

Find the value of x and and band the substitution method.

$(I)-5x+and=8$

$(II)3x-2and=11$

$x=-\frac{27}{7},y=-\frac{79}{7}$

Find the value of x and and band the substitution method.

$(I)-4x+4and=15$

$(II)2x+8and=12$

$x=-\frac{9}{5},y=\frac{39}{20}$

Choose the correct answer for the following exercise:

$(I)x+y=15$

$(II)2x+2y=12\frac{}{}$

No solution

Choose the correct answer for the following exercise:

$(I)-2x+3y=14$

$(II)-4x+6y=28$

Infinite solutions

Find the value of x and and band the substitution method.

$(I)x+4and=5-3and$

$(II)2x+3and=6$

$x=\frac{27}{11},y=\frac{4}{11}$

Find the value of x and and band the substitution method.

$(I)8x-2and=10$

$(II)3x+3and=9$

$x=\frac{8}{5},y=\frac{14}{10}$

Choose the correct answer for the following exercise:

$(I)-8x+5y=10$

$(II)-24x+15y=30$

Infinite solutions

Solve the following equations for x and y using the substitution method:

$(I)\frac{2x-y}{2}+\frac{-3y+x}{5}=7$

$(II)\frac{-y-x}{8}-\frac{5y+x}{6}=4$

$x=1.57,y=-4.65$

Choose the correct answer for the following exercise:

$(I)3x-4y=10$

$(II)9x-12y=15$

No solution

Look at the two equations below. Calculate the values of x and y using the substitution method.

$\begin{cases}\frac{x-y}{2}+\frac{-y+x}{3}=-6 \\ \frac{-y-x}{5}-\frac{y+x}{1}=8\end{cases}$

$x=-6.933,y=0.266$

Choose the correct answer for the following exercise:

$(I)-8x+5y=2$

$(II)-16x+10y=5$

No solution

Solve the following equations for x and y using the substitution method:

$(I)\frac{2x-3y}{4}+\frac{x-y}{5}=30$

$(II)\frac{2y+x}{8}-\frac{3y-x}{4}=12$

$x=-576,y=-456$

Solve the following equations for x and y using the substitution method.

$(I)\frac{3x-2y}{8}+\frac{x-y}{2}=14$

$(II)\frac{4x+3y}{5}-\frac{2x-2y}{3}=20$

$x=27.08,y=12.93$

Solve the following equations for x and y using the substitution method.

$(I)\frac{-x+3y}{6}+\frac{5x-y}{3}=12$

$(II)\frac{2x-4y}{10}-\frac{-2x-2y}{5}=15$

$x=25,y=-153$