Associative Property: Only addition and subtraction

Let's break down 4 into a smaller addition problem:

$3+1$

Now we'll get the exercise:

$3+1+9+8=$

Since the exercise only involves addition, we'll use the commutative property and start with the exercise:

$1+9=10$

Now we'll get the exercise:

$3+10+8=$

Let's solve the exercise from right to left:

$10+8=18$

$18+3=21$

We will use the commutative property and first solve the addition exercise on the right:

$2+8=10$

Now we get:

$13+10=23$

First, we'll solve the left-hand side of the exercise since adding these numbers together gives us a round number:

$13+7=20$

This leaves us with a much easier exercise to solve:

$20+100=120$

First, solve the left exercise since adding the numbers together will give us a round number:

$8+2=10$

Now we have an easier exercise to solve:

$10+7=17$

First, solve the right-hand side of the exercise since adding these numbers together will give you a round number:

$2+8=10$

This leaves you with an easier exercise to solve:

$38+10=48$

First, solve the right-hand exercise since adding the numbers together will give us a round number:

$5+5=10$

Now we have an easier exercise to solve:

$13+10=23$

First, we'll combine the lower numbers using the commutative property:

$5+1=6$

Now we'll get the exercise:

$32+6=38$

Let's break down 560 into a smaller addition exercise and we get:

$24+2+560+2=$

Now let's use the commutative property and add the smaller numbers:

$24+2+2=26+2=28$

Now we get the exercise:

$28+560=$

Let's break down 28 into a smaller addition exercise:

$20+8+560$

Let's group the round numbers:

$20+560=580$

And we get the exercise:

$580+8=588$

Note that the right-hand side of the addition exercise between the fractions gives a result of a whole number, so we'll start with that:

$6\frac{2}{3}+\frac{1}{3}=7$

Giving us:

$7\frac{5}{6}+7=14\frac{5}{6}$

Let's solve the exercise from left to right.

We will combine the left expression in the following way:

$\frac{6+8}{7}x=\frac{14}{7}x=2x$

Now we get:

$2x+3\frac{2}{3}x=5\frac{2}{3}x$

According to the rules of the order of operations in arithmetic, we solve the exercise from left to right.

Let's note that:

$\frac{1}{3}+\frac{2}{3}=\frac{3}{3}=1$

We should obtain the following exercise:

$1+2\frac{3}{4}=3\frac{3}{4}$

According to the order of operations, we will solve the exercise from left to right.

Let's note that in the first addition exercise, we have an addition between two halves that will give us a whole number, so:

$\frac{1}{2}+3\frac{1}{2}=4$

Now we will get the exercise:

$4+4\frac{2}{4}=$

Let's note that we can simplify the mixed fraction:

$\frac{2}{4}=\frac{1}{2}$

Now the exercise we get is:

$4+4\frac{1}{2}=8\frac{1}{2}$

According to the order of operations, we will solve the exercise from left to right.

We will first calculate the addition exercise in the vertical column, since it contains two numbers after the decimal point:

$0.85+7.61=8.46$

Now we will get the exercise:

$8.46+2.3=$

Let's remember that:

$2.3=2.30$

We will calculate in the vertical column and get:

$10.76$

First we will break down each of the factors in the exercise into a whole number and its remainder:

$8+0.5+5+0.2+8+0.4=$

Now we'll combine only the whole numbers:

$8+5+8=13+8=21$

Then we'll calculate the remainder:

$0.5+0.2+0.4=0.7+0.4=1.1$

Finally, we are left with the following:

$21+1.1=22.1$

According to the order of operations rules, we'll solve the exercise from left to right:

$0.2x+8.6x=8.8x$

We'll break down 8.8 into a smaller addition exercise that will be easier for us to calculate:

$8x+0.8x+0.65x=$

Now we'll use the commutative property since the exercise only involves addition.

Let's focus on the leftmost addition exercise, remembering that:

$0.8=0.80$$$

We'll calculate the following exercise:

$0.80x+0.65x=1.45x$

And finally, we'll get the exercise:

$8x+1.45x=9.45x$

The first step is factorising each of the terms in the exercise into a whole number and its remainder:

$10x+0.1x+5x+0.2x+2x+0.4x=$

Now we'll combine only the whole numbers:

$10x+5x+2x=15x+2x=17x$

Next, we will calculate the remainder:

$0.1x+0.2x+0.4x=0.3x+0.4x=0.7x$

Finally, we are left with the following:

$17x+0.7x=17.7x$

First, let's find a common denominator for 4, 8, and 6: it's 24.

Now, we'll multiply each fraction by the appropriate number to get:

$\frac{5\times4}{6\times4}x+\frac{7\times3}{8\times3}x+\frac{2\times6}{4\times6}x=$

Let's solve the multiplication exercises in the numerator and denominator:

$\frac{20}{24}x+\frac{21}{24}x+\frac{12}{24}x=$

We'll connect all the numerators:

$\frac{20+21+12}{24}x=\frac{41+12}{24}x=\frac{53}{24}x$

Let's break down the numerator into a smaller addition exercise:

$\frac{48+5}{24}=\frac{48}{24}+\frac{5}{24}=2+\frac{5}{24}=2\frac{5}{24}x$