Additional Arithmetic Rules: Using multiple rules

$130:\frac{10}{2x}-(23x-204)=\text{?}$

$3x+204$

$300:(20\cdot8)-(13+200)=\text{?}$

$-211\frac{1}{8}$

$28:(210:15)-(12+42)=\text{?}$

$-52$

$39:(x\cdot3)+\frac{y}{x}:\frac{y}{4}=\text{?}$

$\frac{17}{x}$

$35-(400:\frac{20}{13}-12)=\text{?}$

$-213$

$1-(4\cdot13\cdot7:\frac{2}{26}-13\cdot13\cdot7\cdot4)=?$

1

$3x-(y\cdot z+3z:\frac{z}{x})=\text{?}$

$-yz$

$48:\frac{10}{x}-(x+5)=\text{?}$

$3.8x-5$

$35-(82-39:(3\cdot2))=\text{?}$

$-40\frac{1}{2}$

$124-(38-92)-(56+33)=\text{?}$

89

$78-(39-47)-(95+3:\frac{3}{5})=\text{?}$

$-14$

$-55-(-94-(-32))+12:\frac{3}{4}=\text{?}$

$23$

$-450:\frac{50}{-3}-((-3x)+(-14))=\text{?}$

$41+3x$

$\frac{a^2}{2}:\frac{a}{3}-(3a+12:(4a\cdot3))=\text{?}$

$-1.5a-\frac{1}{a}$

$\frac{1}{2}-(\frac{1}{4}:\frac{8}{9}+\frac{3}{4}:(4\cdot3))=\text{?}$

$\frac{5}{32}$

$abc-(ab:\frac{2}{c}+ab^2c^2:(b\cdot c))=\text{?}$

$-\frac{1}{2}abc$

$27-(140:\frac{35}{3}+360:(8\cdot9))=\text{?}$

$10$

$18-((560:\frac{70}{3}-14)-9)=\text{?}$

$17$

$35:(7\cdot5)-(2+9:\frac{3}{2})=\text{?}$

7-

$79-(35-(-9))-(10+43)=\text{?}$

18-