Subtract 5 from 473: Vertical Format Arithmetic Problem

Video Solution

Solution Steps

00:00 Solve

00:03 Each time consider a shortage of 2 digits, and then we'll place

00:06 3 is less than 5

00:09 So we'll subtract 1 from the tens and add this amount to the ones

00:15 In other words, instead of 3 we'll now have 13

00:18 We'll subtract the ones from the ones plus the carried ten

00:23 Place in ones

00:26 Place 0 in the missing digits

00:31 Subtract tens from tens, and place in tens

00:35 Subtract hundreds from hundreds, and place in hundreds

00:38 And this is the solution to the problem

Step-by-Step Solution

To solve this problem, we'll perform a vertical subtraction:

Step 1: Set up the subtraction vertically
Write the larger number, 473, above and align the smaller number, 5, beneath it on the far right:

$\begin{aligned} &473 \\ -& \\ &~~~5 \\ \underline{\phantom{776}} & \\ \end{aligned}$

Step 2: Subtract each column, starting from the right
- Units: We have 3 minus 5. Since 3 is smaller than 5, we need to regroup by borrowing. Take 1 ten from the tens place.
- After borrowing, the tens digit decreases by 1 (from 7 to 6), and the units place becomes 13 (3 + 10 = 13).
- Now, subtract 5 from 13, which equals 8.
Step 3: Move to the tens column
- After borrowing, subtract 0 from 6, which leaves 6.
Step 4: Move to the hundreds column
- Finally, subtract 0 from 4, which leaves 4.

The result of the subtraction is:

\begin{aligned} & 473 \\ -& \\ &~~~5 \\ \underline{~~~~~} & \\ & 468 \\ \end{aligned}

Therefore, the solution to the problem is $468$ .