Solve (x·y·z) ÷ (xy/z): Complex Variable Expression Division

Fraction Division with Variable Simplification

Solve the following problem:

(xyz):xyz=? (x\cdot y\cdot z):\frac{xy}{z}=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Division is also multiplication by reciprocal
00:14 Make sure to multiply numerator by numerator and denominator by denominator
00:24 Simplify what we can
00:28 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

(xyz):xyz=? (x\cdot y\cdot z):\frac{xy}{z}=\text{?}

2

Step-by-step solution

Let's flip the fraction to get a multiplication exercise:

(xyz)×zxy= (x\cdot y\cdot z)\times\frac{z}{xy}=

We'll add the multiplication exercise in parentheses to the numerator of the fraction:

x×y×z×zxy= \frac{x\times y\times z\times z}{xy}=

We'll simplify the x and y in the numerator and denominator of the fraction:

z×z1=z2 \frac{z\times z}{1}=z^2

3

Final Answer

z2 z^2

Key Points to Remember

Essential concepts to master this topic
  • Division Rule: Dividing by a fraction means multiplying by its reciprocal
  • Technique: (xyz)÷xyz=xyz×zxy (xyz) \div \frac{xy}{z} = xyz \times \frac{z}{xy}
  • Check: Substitute values like x=2, y=3, z=4 to verify z2=16 z^2 = 16

Common Mistakes

Avoid these frequent errors
  • Trying to divide variables directly without converting to multiplication
    Don't attempt xyz÷xyz xyz \div \frac{xy}{z} by separating variables = confusion and wrong steps! Division by fractions becomes messy without the reciprocal. Always flip the fraction first: xyz×zxy xyz \times \frac{z}{xy} , then cancel common factors.

Practice Quiz

Test your knowledge with interactive questions

\( 100-(5+55)= \)

FAQ

Everything you need to know about this question

Why do I flip the fraction when dividing?

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Division by a fraction is the same as multiplication by its reciprocal. So ÷xyz \div \frac{xy}{z} becomes ×zxy \times \frac{z}{xy} . This makes the problem much easier to solve!

How do I know which variables cancel out?

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Look for identical variables in the numerator and denominator. In xyz×zxy \frac{xyz \times z}{xy} , the x and y appear in both top and bottom, so they cancel completely.

What if the variables have different exponents?

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Subtract the exponents when canceling! For example, x3x2=x32=x1=x \frac{x^3}{x^2} = x^{3-2} = x^1 = x . In our problem, we have z2z0=z2 \frac{z^2}{z^0} = z^2 since z only appears in the numerator.

Can I check my answer with actual numbers?

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Absolutely! Try x=2, y=3, z=4. Original expression: (2×3×4)÷2×34=24÷1.5=16 (2 \times 3 \times 4) \div \frac{2 \times 3}{4} = 24 \div 1.5 = 16 . Our answer z2=42=16 z^2 = 4^2 = 16

What if one of the variables equals zero?

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Be careful! If x or y equals zero, the fraction xyz \frac{xy}{z} becomes zero, and you'd be dividing by zero (undefined). If z equals zero, the original fraction is undefined.

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