Solve (x+?)(x+?) = x²+7x+10: Finding Missing Terms in Quadratic Factors

Question

(x+?)(x+?)=x2+7x+10 (x+?)(x+?)=x^2+7x+10

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the pattern of factoring quadratics.
  • Step 2: Use the sum and product relation to find the numbers.
  • Step 3: Confirm the binomial expressions.

Let's work through each step:

Step 1: Our task is to factor the expression x2+7x+10x^2 + 7x + 10. We need two numbers whose product is 1010 (the constant term) and whose sum is 77 (the coefficient of xx).

Step 2: We list pairs of numbers that multiply to 1010:
- 1×101 \times 10
- 2×52 \times 5

Among these, only the pair 22 and 55 add up to 77. Therefore, the expressions needed are (x+2)(x+2) and (x+5)(x+5).

Step 3: We substitute these values into the binomials: (x+5)(x+2)(x+5)(x+2). Expanding this verifies:
(x+5)(x+2)=x2+2x+5x+10=x2+7x+10(x+5)(x+2) = x^2 + 2x + 5x + 10 = x^2 + 7x + 10.

Therefore, the factorization is correct, and the solution reached is (x+5)(x+2)\left(x+5\right)\left(x+2\right).

Therefore, the solution to the problem is (x+5)(x+2)\left(x+5\right)\left(x+2\right).

Answer

(x+5)(x+2) \left(x+5\right)\left(x+2\right)