Solve (x+3)(x-3) = x²+x: Expanding Brackets Problem

Let's examine the given equation:

$(x+3)(x-3)=x^2+x$First, let's simplify the equation, for this we'll use the difference of squares factoring formula:

$(a+b)(a-b)=a^2-b^2$,

We'll start by opening the parentheses on the left side using the mentioned factoring formula, then we'll move terms, combine like terms, and finally solve the resulting equation:

$(x+3)(x-3)=x^2+x \\ \downarrow\\ x^2-3^2=x^2+x \\ x^2-9=x^2+x \\ x^2-9-x^2-x=0 \\ \boxed{x=-9}$Therefore, the correct answer is answer B.