Solve the Vertical Addition: 289 + 1 Step by Step

Video Solution

Solution Steps

00:00 Solve

00:03 Each time consider combining 2 digits, and then place

00:06 Let's start by combining ones with ones

00:12 Place the ones in ones, add 1 to tens

00:16 Place 0 in the missing digits

00:19 Add the tens, remember to add 1, and place in tens

00:28 Place 0 in the missing digits

00:31 Add the hundreds, and place in hundreds

00:34 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll use vertical addition:

Step 1: Align the numbers vertically so that the digits of each place value line up:
$\begin{array}{c} 289 \\ +1 \\ \underline{\phantom{776}} \\ \end{array}$
Step 2: Start adding from the rightmost column, the units place:
$9 + 1 = 10$ . Write $0$ in the units place and carry over $1$ to the tens place.
Step 3: Move to the tens column, add the tens digits and the carry-over $1$ :
$8 + 0 + 1 = 9$ . Place $9$ in the tens place.
Step 4: Move to the hundreds column, add the remaining numbers:
$2 + 0 = 2$ . Place $2$ in the hundreds place.

The total sum reflects in the alignment:

$\begin{array}{c} 289 \\ +1 \\ \underline{\phantom{776}} \\ 290 \end{array}$

Therefore, the solution to the problem is $290$ .