Solve the Quadratic Equation: x²-3x-18=0 Step-by-Step

Question

x23x18=0 x^2-3x-18=0

Video Solution

Solution Steps

00:00 Find X
00:03 Let's break it down using trinomial, let's look at the coefficients
00:07 We want to find 2 numbers whose sum equals B (-3)
00:13 and their product equals C (-18)
00:20 These are the matching numbers, let's substitute in parentheses
00:30 Let's find what zeros each factor
00:39 And this is the solution to the question

Step-by-Step Solution

Let's observe that the given equation:

x23x18=0 x^2-3x-18=0 is a quadratic equation that can be solved using quick factoring:

x23x18=0{??=18?+?=3(x6)(x+3)=0 x^2-3x-18=0 \longleftrightarrow\begin{cases}\underline{?}\cdot\underline{?}=-18\\ \underline{?}+\underline{?}=-3\end{cases}\\ \downarrow\\ (x-6)(x+3)=0 and therefore we get two simpler equations from which we can extract the solution:

(x6)(x+3)=0x6=0x=6x+3=0x=3x=6,3 (x-6)(x+3)=0 \\ \downarrow\\ x-6=0\rightarrow\boxed{x=6}\\ x+3=0\rightarrow\boxed{x=-3}\\ \boxed{x=6,-3} Therefore, the correct answer is answer A.

Answer

x=3,x=6 x=-3,x=6