Solve the Quadratic Equation: 4x² + 1 = 0 with Complex Solutions

Question

Solve the following equation

4x2+1=0 4x^2+1=0

Video Solution

Solution Steps

00:00 Find X
00:03 Isolate X
00:15 Any number squared is necessarily greater than 0, meaning it's positive
00:24 In our equation, the unknown squared equals a negative number
00:34 Therefore there is no solution to the question

Step-by-Step Solution

First, we'll identify that the quadratic equation:

4x2+1=0 4x^2+1=0

and this is because there is a quadratic term (meaning raised to the second power),

The first step in solving a quadratic equation is always arranging it in a form where all terms on one side are ordered from highest to lowest power (in descending order from left to right) and 0 on the other side,

Then we can choose whether to solve it using the quadratic formula or by factoring/completing the square.

The equation in the problem is already arranged, so let's proceed with the solving technique:

We'll choose to solve it using the quadratic formula,

Let's recall it first:

The rule states that the roots of an equation in the form:

ax2+bx+c=0 ax^2+bx+c=0

are:

x1,2=b±b24ac2a x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

(meaning its solutions, the two possible values of the unknown for which we get a true statement when substituted in the equation)

This formula is called: "The Quadratic Formula"

Let's return to the problem:

4x2+1=0 4x^2+1=0 and solve it:

First, let's identify the coefficients of the terms:

{a=4b=0c=1 \begin{cases}a=4 \\ b=0 \\ c=1\end{cases}

Note that in the given equation there is no first-power term, so from comparing to the general form:

ax2+bx+c=0 ax^2+bx+c=0

we can conclude that the coefficient b b (which is the coefficient of the first-power term x x in the general form) is 0,

Let's continue and get the equation's solutions (roots) by substituting the coefficients we noted earlier in the quadratic formula:

x1,2=b±b24ac2a=0±0244124 x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{0\pm\sqrt{0^2-4\cdot4\cdot1}}{2\cdot4}

Let's continue and calculate the expression under the root and simplify the expression:

x1,2=±168 x_{1,2}=\frac{\pm\sqrt{-16}}{8}

We got a negative expression under the root, and since we cannot extract a real root from a negative number, this equation has no real solutions,

In other words - there is no real value of x x that when substituted in the equation will give a true statement.

Therefore, the correct answer is answer D.

Answer

No solution