80−(4−12)= 80-(4-12)= 80−(4−12)=
According to the order of operations, we first solve the exercise within parentheses:
4−12=−8 4-12=-8 4−12=−8
Now we obtain the exercise:
80−(−8)= 80-(-8)= 80−(−8)=
Remember that the product of plus and plus gives us a positive:
−(−8)=+8 -(-8)=+8 −(−8)=+8
Now we obtain:
80+8=88 80+8=88 80+8=88
88 88 88