∣−3x∣=15 \left|-3x\right|=15 ∣−3x∣=15
To solve ∣−3x∣=15 \left|-3x\right|=15 ∣−3x∣=15, we consider both potential cases stemming from the absolute value:
1) −3x=15-3x=15−3x=15:
Divide both sides by −3-3−3 to get x=−5x=-5x=−5.
2) −3x=−15-3x=-15−3x=−15:
Divide both sides by −3-3−3 to get x=5x=5x=5.
Thus, the solutions are x=−5 x=-5x=−5 and x=5 x=5x=5.
x=−5 x=-5 x=−5 , x=5 x=5 x=5