Solve (m+n)(4+?) = n²+mn+4m+4n: Find the Missing Term

Complete the missing element

(m+n)(4+?)=n2+mn+4m+4n (m+n)(4+?)=n^2+mn+4m+4n

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing term
00:03 Open parentheses properly, multiply each factor by each factor
00:34 Group terms and reduce what's possible
00:50 Compare the corresponding terms
00:55 This is the value ?, now let's check if it fits
01:02 Compare the corresponding terms, find the value ? we found
01:10 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the missing element

(m+n)(4+?)=n2+mn+4m+4n (m+n)(4+?)=n^2+mn+4m+4n

2

Step-by-step solution

To solve this problem, we'll apply the distributive property to expand and match the expressions:

  • Step 1: Expand (m+n)(4+?)(m+n)(4+?) using distributive property: (m+n)(4+n)=m(4+n)+n(4+n) (m+n)(4+n) = m(4+n) + n(4+n) .
  • Step 2: This gives us 4m+mn+4n+n2 4m + mn + 4n + n^2 .
  • Step 3: Compare this to the expression n2+mn+4m+4n n^2 + mn + 4m + 4n .

The expanded expression matches the target expression, so the missing term in (m+n)(4+?)(m+n)(4+?) is indeed nn.

Therefore, the complete expression is (m+n)(4+n)(m+n)(4+n).

3

Final Answer

n n

Practice Quiz

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\( (3+20)\times(12+4)= \)

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