Solve for Missing Terms in 23x(? + ?) = 46x² + 23

Question

Fill in the missing values:

23x(?+?)=46x2+23 23x(?+?)=46x^2+23

Video Solution

Step-by-Step Solution

To solve this problem, let's consider how the equation is structured:

The given equation is 23x(?+?)=46x2+23 23x(?+?) = 46x^2 + 23 .

On the left-hand side, we have 23x×(?+?) 23x \times (?+?) and on the right-hand side, we observe it's structured as a multiplication between two terms plus a constant.

Re-examine the right-hand side, 46x2+23 46x^2 + 23 . This can be interpreted as (2x)(23x)+23 (2x) \cdot (23x) + 23 .

The expression can be rearranged as:
23(2xx+1) 23 \cdot (2x \cdot x + 1) .

Therefore, the original equation takes the form:
23x(2x+1x) 23x(2x + \frac{1}{x}) , also known as multiplying through distribution yields,
23x2x+23x1x=46x2+23 23x \cdot 2x + 23x \cdot \frac{1}{x} = 46x^2 + 23 ,
which matches perfectly with 46x2+23 46x^2 + 23 .

By comparing the elements, we find that the missing parts are:

  • The first missing part is 2x 2x .
  • The second missing part is 1x \frac{1}{x} .

Hence, the values for the question marks are 2x 2x and 1x \frac{1}{x} .

Therefore, the correct answer is:

2x,1x 2x,\frac{1}{x}

Answer

2x,1x 2x,\frac{1}{x}