Solve: (a+b+c)÷((3a+3b+3c)/2) - Expression Division Problem

Let's flip the fraction to get a multiplication exercise:

$(a+b+c)\times(\frac{2}{3a+3b+3c})=$

We'll add the expression in the first parentheses to the numerator of the fraction:

$\frac{2(a+b+c)}{3a+3b+3c}=$

We'll write the denominator of the fraction as a multiplication exercise:

$\frac{2(a+b+c)}{3(a+b+c)}=$

Let's simplify a+b+c:

$\frac{2}{3}$