Simplify the Fraction: (4³)/(5³×7³) Step-by-Step Solution

Insert the corresponding expression:

4353×73= \frac{4^3}{5^3\times7^3}=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's simplify this problem together.
00:12 Remember that when a product is raised to a power, N, it's like raising each factor to that same power.
00:19 So, we'll break it down and apply this to our exercise. Watch as we use parentheses.
00:24 Now, let's talk about raising a fraction to a power, N.
00:29 This means both the top and bottom numbers are raised to that power, N.
00:34 We'll use this idea to write our expression as a fraction with a power in parentheses.
00:41 And there you have it!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

4353×73= \frac{4^3}{5^3\times7^3}=

2

Step-by-step solution

To solve this problem, we will apply the rule for powers of a quotient. By recognizing that the expression 4353×73 \frac{4^3}{5^3 \times 7^3} can be seen in terms of powers, we can reformulate it:

4353×73=43(5×7)3 \frac{4^3}{5^3 \times 7^3} = \frac{4^3}{(5 \times 7)^3}

Now, we see this as a single fraction raised to the same power, which can be expressed using the power of a fraction rule:

43(5×7)3=(45×7)3 \frac{4^3}{(5 \times 7)^3} = \left(\frac{4}{5 \times 7}\right)^3

Thus, the expression given is equivalent to

(45×7)3 \left(\frac{4}{5 \times 7}\right)^3 .

3

Final Answer

(45×7)3 \left(\frac{4}{5\times7}\right)^3

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Exponents Rules questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations