Simplify the Expression: 25x+33y+6z-(14-(-12y)-3z)

Question

25x+33y+6z(14(12y)3z)=? 25x+33y+6z-(14-(-12y)-3z)=\text{?}

Video Solution

Solution Steps

00:00 Solve
00:03 Always solve parentheses first
00:07 Always solve the "innermost" parentheses first
00:12 Note, negative times negative is always positive
00:26 Note, negative times positive is always negative
00:36 Note, negative times negative is always positive
00:47 Group terms
01:03 And this is the solution to the question

Step-by-Step Solution

First, let's address the expression in the innermost parentheses.

Let's remember that:

When we multiply a negative number by a negative number, the result will be positive.

Now we get:

25x+33y+6z(14+12y3z)= 25x+33y+6z-(14+12y-3z)=

Let's address the expression in parentheses and also remember the rule:

When we multiply a positive number by a negative number, the result will be negative.

We get:

25x+33y+6z1412y+3z= 25x+33y+6z-14-12y+3z=

Now let's combine the y coefficients:

33y12y=21y 33y-12y=21y

Now let's combine the z coefficients:

6z+3z=9z 6z+3z=9z

And we get:

25x+21y+9z14 25x+21y+9z-14

Answer

25x+21y+9z14 25x+21y+9z-14