Multiply Square Roots: √1 × √2 × √3 Solution Guide

Question

Solve the following exercise:

123= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3}=

Video Solution

Solution Steps

00:00 Simplify the expression
00:03 The root of a number (A) times the root of another number (B)
00:07 equals the root of their product (A times B)
00:11 Let's use this formula in our exercise, and convert to a single root
00:15 Let's calculate the products
00:21 And this is the solution to the question

Step-by-Step Solution

In order to simplify the given expression, we will use two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for exponents applied to terms in parentheses (in reverse order):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Let's start by converting the square roots to exponents using the law of exponents mentioned in a':

123112212312= \sqrt{1}\cdot\sqrt{2}\cdot\sqrt{3} \\ \downarrow\\ 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}=

We'll continue, since there is multiplication between three terms with identical exponents, we can use the law of exponents mentioned in b' (which also applies to multiplication of several terms in parentheses) and combine them together in multiplication under parentheses raised to the same exponent:

112212312=(123)12=612=6 1^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}= \\ (1\cdot2\cdot3)^{\frac{1}{2}}=\\ 6^{\frac{1}{2}}=\\ \boxed{\sqrt{6}}

In the final steps, we performed the multiplication within the parentheses and again used the definition of root as an exponent mentioned in a' (in reverse order) to return to root notation.

Therefore, the correct answer is answer d.

Answer

6 \sqrt{6}