Long Division Problem: Divide 20035 by 6 Step-by-Step

Video Solution

Solution Steps

00:00 Solve

00:04 Let's start by dividing the leftmost digit in the dividend

00:07 2 is less than 6, so we'll bring down the next digit, and then divide

00:11 Write the result without remainder above, paying attention to position

00:15 Now multiply the result by the divisor

00:19 Subtract the product from the number

00:24 Now bring down the next digit and use the same steps

00:29 We got the same number, so we'll use the same calculations

00:35 Now bring down the next digit and use the same steps

00:42 Divide

00:46 Write the result without remainder above, paying attention to position

00:50 Multiply the result and subtract

00:55 Now bring down the next digit and use the same steps

00:59 Divide

01:03 Write the result without remainder above, paying attention to position

01:09 Multiply the result and subtract

01:15 We got a remainder of 1

01:19 And this is the solution to the problem

Step-by-Step Solution

To solve this problem, we'll perform long division of 20035 by 6:

Step 1: Divide 20 by 6.
- 6 goes into 20 three times (since $6 \times 3 = 18$ ), leaving a remainder of 2.
- Write the 3 in the quotient, and bring down the next digit, 0, to make 20.
Step 2: Divide 20 by 6 again.
- 6 goes into 20 three times (same calculation as before), leaving a remainder of 2.
- Write the next 3 in the quotient, and bring down the next digit, 0, to make 23.
Step 3: Divide 23 by 6.
- 6 fits into 23 three times (since $6 \times 3 = 18$ ), leaving a remainder of 5.
- Write the next 3 in the quotient, and bring down the next digit, 5, to make 55.
Step 4: Divide 55 by 6.
- 6 fits into 55 nine times (since $6 \times 9 = 54$ ), leaving a remainder of 1.

The resultant quotient is 3339, with a remainder of 1.

Therefore, the solution to the problem is $3339$ with a remainder of 1.