Finding Roots of x² + 5x + 4: Quadratic Equation Solution

Question

Solve the following equation:

$x^2+5x+4=0$

00:00 Find X

00:03 Pay attention to the coefficients

00:13 Use the roots formula

00:22 Substitute appropriate values according to the given data and solve for X

00:42 Calculate the products and square

00:52 Calculate the square root of 9

01:00 Find the 2 possible solutions

01:08 This is one solution

01:15 And this is the second solution, and the answer to the question

The parameters are expressed in the quadratic equation as follows:

aX2+bX+c=0

We substitute into the formula:

-5±√(5²-4*1*4)
2

-5±√(25-16)
2

-5±√9
2

-5±3
2

The symbol ± means that we have to solve this part twice, once with a plus and a second time with a minus,

This is how we later get two results.

-5-3 = -8
-8/2 = -4

-5+3 = -2
-2/2 = -1

And thus we find out that X = -1, -4

$x_1=-1$ $x_2=-4$