Factorize the Expression: (16xy/z + 40x/yz - 56x²/yz²)

Question

Decompose the following expression into factors:

16xyz+40xyz56x2yz2 \frac{16xy}{z}+\frac{40x}{yz}-\frac{56x^2}{yz^2}

Video Solution

Step-by-Step Solution

To solve this problem, we'll proceed with the following steps:

  • Step 1: Identify the greatest common factor in the expression.
  • Step 2: Factor out this common factor from each term.
  • Step 3: Simplify the resulting expression inside the parentheses.

Now, let's work through each step:

Step 1: The expression given is
16xyz+40xyz56x2yz2 \frac{16xy}{z}+\frac{40x}{yz}-\frac{56x^2}{yz^2} .
First, identify the greatest common factor (GCF) from the numerators and the highest common power in the denominators:

  • The coefficients of the terms are 1616, 4040, and 5656, with a GCF of 88.
  • The common variable in the numerators is xx.
  • The shared parts of the denominators are zz.

Thus, the GCF for the entire expression with terms considered is:

8xz \frac{8x}{z} .

Step 2: Factor out 8xz\frac{8x}{z} from the expression:

8xz(16xy8x40x8xy+56x28xy2)8xz(2y+5y7xyz) \frac{8x}{z} \left( \frac{16xy}{8x}-\frac{40x}{8x}y+\frac{56x^{2}}{8x}y^{2} \right) \equiv \frac{8x}{z}(2y + \frac{5}{y} - \frac{7x}{yz}) .

Step 3: The expression in the parentheses should now be simplified:
After factoring, the expression inside the parentheses becomes 2y+5y7xyz2y+\frac{5}{y}-\frac{7x}{yz}.

Therefore, the factored form of the original expression is:

8xz(2y+5y7xyz) \frac{8x}{z}(2y+\frac{5}{y}-\frac{7x}{yz}) .

Answer

8xz(2y+5y7xyz) \frac{8x}{z}(2y+\frac{5}{y}-\frac{7x}{yz})