(2[x+3])2= (2\lbrack x+3\rbrack)^2= (2[x+3])2=
We will first solve the exercise by opening the inner brackets:
(2[x+3])²
(2x+6)²
We will then use the shortcut multiplication formula:
(X+Y)²=X²+2XY+Y²
(2x+6)² = 2x² + 2x*6*2 + 6² = 2x+24x+36
4x2+24x+36 4x^2+24x+36 4x2+24x+36