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We will first solve the exercise by opening the inner brackets:
(2[x+3])²
(2x+6)²
We will then use the shortcut multiplication formula:
(X+Y)²=X²+2XY+Y²
(2x+6)² = 2x² + 2x*6*2 + 6² = 2x+24x+36
Choose the expression that has the same value as the following:
\( (x+3)^2 \)
Because (a+b)² ≠ a² + b²! You're missing the middle term 2ab. The correct formula is , which gives you three terms, not two.
Yes! Always work from the inside out. First expand 2[x+3] = 2x+6, then square the result. This makes the problem much clearer and prevents errors.
Think "First, twice, last": square the first term, add twice the product of both terms, then square the last term. Practice with simple examples like .
The middle term is always 2ab where a and b are your two terms. In (2x+6)², that's 2 × 2x × 6 = 24x. Double-check by multiplying the terms and doubling the result!
Absolutely! FOIL works perfectly: (2x+6)(2x+6) = First + Outer + Inner + Last = 4x² + 12x + 12x + 36 = 4x² + 24x + 36. Both methods give the same answer.
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