What is Michael's score if he gets 79 on the first exam and 83 on the second, given that the weight of the first test is 30% and that of the second is 70%?
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What is Michael's score if he gets 79 on the first exam and 83 on the second, given that the weight of the first test is 30% and that of the second is 70%?
To solve the weighted average, we will use the following formula:
exam 2 * weight of evaluation 2 + exam 1 * weight of the evaluation 1 = Weighted average
We will place the data in the formula, where the weights will be in decimal numbers:
0.3*79 + 0.7*83 =
23.7+58.1 =
81.8
Norbert buys some new clothes.
When he gets home, he decides to work out how much each outfit cost him on average.
What answer should he come up with?
A regular average treats both scores equally, but weighted averages give more importance to certain scores. Here, the second exam (83) counts for 70% while the first (79) only counts for 30%.
Simply divide by 100! 30% = 30 ÷ 100 = 0.3 and 70% = 70 ÷ 100 = 0.7. This makes the multiplication easier.
Yes! Your weighted average should fall between 79 and 83. Since the higher score (83) has more weight, the result should be closer to 83 than to 79.
Check your problem again! In most cases, weights should total 100%. If they don't, you might need to normalize them or ask your teacher for clarification.
Absolutely! Just add more terms: and so on. The weights should still total 100%.
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