Calculate First Five Terms: Sequence Formula an=3n+1

Question

Given the series, y represents some term of the series

n represents the position of the term in the series

What are the first five members of the series?

an=3n+1 a_n=3n+1

Video Solution

Solution Steps

00:00 Find the first five terms in the sequence
00:04 We'll place the appropriate term's position in the formula and solve
00:13 Always solve multiplication and division before addition and subtraction
00:16 This is the first term in the sequence
00:20 We'll use the same method to find the rest of the terms
00:29 This is the second term in the sequence
00:43 This is the third term in the sequence
01:00 This is the fourth term in the sequence
01:11 And this is the solution to the question

Step-by-Step Solution

Let's find the first five terms in the sequence by substituting their positions in the given general term formula:

an=3n+1 a_n=3n+1

We want to calculate the values of the terms:

a1,a2,a3,a4,a5 a_1,\hspace{4pt}a_2,\hspace{4pt}a_3,\hspace{4pt}a_4,\hspace{4pt}a_5

Let's start with the first term in the sequence,

meaning in the given general term formula:

an=3n+1 a_n=3n+1

We need to substitute the position (of the requested term in the sequence),

We want to find the first term so we'll substitute:

n=1 n=1

Let's perform this:

an=3n+1n=1a1=31+1=4 a_{\underline{n}}= 3\underline{n}+1 \\ n=\underline{1}\\ \downarrow\\ a_{\underline{1}}=3\cdot\underline{1}+1=4

When we substituted in place of n the position (of the requested term in the sequence): 1, the substitution is shown with an underline in the expression above,

We'll repeat this action identically for all the requested terms in the sequence, meaning for the second through fifth terms:

a2=32+1=7a3=33+1=10a4=34+1=13a5=35+1=16 a_{\underline{2}}=3\cdot\underline{2}+1=7 \\ a_{\underline{3}}=3\cdot\underline{3}+1=10 \\ a_{\underline{4}}=3\cdot\underline{4}+1=13 \\ a_{\underline{5}}=3\cdot\underline{5}+1=16 \\ Where for the second term a2 a_2 we substituted:n=2 n=2 in the given general term formula:

an=3n+1 a_n=3n+1

For the third term a3 a_3 we substituted:n=3 n=3 and so on identically for the rest of the requested terms,

To summarize, we found that the first five terms:

a1,a2,a3,a4,a5 a_1,\hspace{4pt}a_2,\hspace{4pt}a_3,\hspace{4pt}a_4,\hspace{4pt}a_5

in the given sequence, are:

4,7,10,13,16 4,\hspace{4pt}7,\hspace{4pt}10,\hspace{4pt}13,\hspace{4pt}16

Therefore, the correct answer is answer A.

Answer

4,7,10,13,16 4,7,10,13,16