Calculate A¹B in an Orthohedron: Given D¹C¹=10 and AA¹=12

Question

Look at the orthohedron below.

$D^1C^1=10$

$AA^1=12$

Calculate $A^1B$ .

00:00 Find A1B

00:03 Face in box is rectangular therefore opposite sides are equal

00:10 Set the side value according to the given data

00:18 Draw the diagonal A1B

00:21 Use Pythagorean theorem in triangle A1AB to find A1B

00:27 Set appropriate values according to the given data and solve to find A1B

00:46 This is the length of diagonal A1B

00:53 Factorize 244 into factors 4 and 61

00:59 And this is the solution to the question

From the given data, we know that:

$D_1C_1=A_1B_1=AB=10$

Let's draw a diagonal between A1 and B and focus on triangle AA1B.

We'll calculate A1B using the Pythagorean theorem:

$AA_1^2+AB^2=A_1B^2$

Then we will substitute in the known values:

$12^2+10^2=A_1B^2$

$A_1B^2=144+100=244$

Finally, we calculate square root:

$A_1B=\sqrt{244}$

$A_1B=\sqrt{4\times61}=\sqrt{4}\times\sqrt{61}$

$A_1B=2\sqrt{61}$

$2\sqrt{61}$