Arithmetic Sequence: Is 1 Present in a Series Starting at 15 with Difference -2?

Arithmetic Sequences with Membership Testing

Given a series whose first element is 15, each element of the series is less by 2 of its predecessor.

Is the number 1 an element of the series?

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Step-by-step video solution

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00:00 Is the number 1 a member of the sequence?
00:03 Let's start calculating jumps of 2 backwards from the first member (15)
00:13 Each time we subtract 2 according to the given
00:35 We can see that 1 is a member of the sequence, and this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given a series whose first element is 15, each element of the series is less by 2 of its predecessor.

Is the number 1 an element of the series?

2

Step-by-step solution

We know that the first term of the series is 15.

From here we can easily write the entire series, until we see if we reach 1.  

15, 13, 11, 9, 7, 5, 3, 1

 

The number 1 is indeed an element of the series!

3

Final Answer

Yes

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use an=a1+(n1)d a_n = a_1 + (n-1)d where d is common difference
  • Technique: Set up equation: 1 = 15 + (n-1)(-2) and solve for n
  • Check: If n is positive integer, number exists in sequence ✓

Common Mistakes

Avoid these frequent errors
  • Just listing terms without using the formula
    Don't just write out 15, 13, 11, 9... hoping to find 1 = waste of time and prone to errors! This method fails for large sequences or when the target isn't in the sequence. Always use the arithmetic sequence formula to solve algebraically.

Practice Quiz

Test your knowledge with interactive questions

Is there a term-to-term rule for the sequence below?

18 , 22 , 26 , 30

FAQ

Everything you need to know about this question

What if I get a negative or fractional value for n?

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If n is negative or a fraction, then the number is not in the sequence! Only positive integers for n mean the number exists as a term in the sequence.

How do I know what the common difference is?

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The common difference is how much you add or subtract to get the next term. In this problem, each term is 2 less than the previous, so d = -2.

Can I just list all the terms to find the answer?

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While listing works for short sequences, it's inefficient and error-prone. Using the formula an=a1+(n1)d a_n = a_1 + (n-1)d is faster and works for any sequence length!

What does it mean when the problem asks 'Is 1 an element of the series'?

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This means: Does 1 appear as one of the terms? We need to determine if there's some position n where the nth term equals exactly 1.

Why do we solve 1 = 15 + (n-1)(-2) instead of just counting?

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Solving algebraically is more reliable and works even when the sequence has hundreds of terms. It also proves definitively whether the number exists or not.

What if my calculation gives n = 8? What does that mean?

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That means 1 is the 8th term in the sequence! You can verify: a8=15+(81)(2)=1514=1 a_8 = 15 + (8-1)(-2) = 15 - 14 = 1

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