Parentheses in simple Order of Operations: Identify the greater value

Let's solve exercise A:

$8\times8=64$

Let's solve exercise B:

$10\times6=60$

Let's solve exercise C:

$12\times5=60$

Let's solve exercise D:

$15\times4=60$

First, we solve the exercise:

$4+7-3+1-5 =$

According to the rules of the order of operations, we solve the exercise from left to right:

$4+7=11$

$11-3=8$

$8+1=9$

$9-5=4$

Now we solve the exercise:

$4+(7-3+1-5) =$

According to the rules of the order of operations, we first solve the parentheses and then we will join:

$(7-3+1-5)=$

$(4+1-5)=$

$(5-5)=0$

$4+0=4$

Therefore:

$4=4$

First, we solve the exercise$14+16:4\times2$According to the order of operations, multiplication and division come before addition and subtraction, therefore we first divide 16 by 4 and then multiply the result by 2:

$16:4=4$

$4\times2=8$

Then, we solve the exercise:
$14+8=22$

Now, we solve the exercise:$14+16:(4\times2)=$

According to the order of operations, the exercise within parentheses is first, so we first multiply 4 by 2 and then proceed to the division operation.

$4\times2=8$

$16:8=2$

In the last step we add:$14+2=16$

Since 22 is greater than 16, the corresponding result is >

We solve the exercise:

$24:6:2=$

According to the rules, we solve the exercise from left to right:

$24:6=4$

$4:2=2$

Now we solve the exercise:

$24:(6:2)=$

According to the rules, first we solve the exercise inside the parentheses and then we divide:

$6:2=3$

$24:3=8$

Therefore:

3 < 8