Solve the following inequality:
5x+8<9
Solve the following inequality:
\( 5x+8<9 \)
Solve the inequality:
\( 5-3x>-10 \)
Solve the inequality:
\( 8x+a < 3x-4 \)
When are the following inequalities satisfied?
\( 3x+4<9 \)
\( 3 < x+5 \)
Find when the inequality is satisfied:
\( -3x+15<3x<4x+8 \)
Solve the following inequality:
5x+8<9
This is an inequality problem. The inequality is actually an exercise we solve in a completely normal way, except in the case that we multiply or divide by negative.
Let's start by moving the sections:
5X+8<9
5X<9-8
5X<1
We divide by 5:
X<1/5
And this is the solution!
x<\frac{1}{5}
Solve the inequality:
5-3x>-10
Inequality equations will be solved like a regular equation, except for one rule:
If we multiply the entire equation by a negative, we will reverse the inequality sign.
We start by moving the sections, so that one side has the variables and the other does not:
-3x>-10-5
-3x>-15
Divide by 3
-x>-5
Divide by negative 1 (to get rid of the negative) and remember to reverse the sign of the equation.
x<5
5 > x
Solve the inequality:
8x+a < 3x-4
Solving an inequality equation is just like a normal equation. We start by trying to isolate the variable (X).
It is important to note that in this equation there are two variables (X and a), so we may not reach a final result.
8x+a<3x-4
We move the sections
8x-3x<-4-a
We reduce the terms
5x<-4-a
We divide by 5
x< -a/5 -4/5
And this is the solution!
x < -\frac{1}{5}a-\frac{4}{5}
When are the following inequalities satisfied?
3x+4<9
3 < x+5
-2 < x < 1\frac{2}{3}
Find when the inequality is satisfied:
-3x+15<3x<4x+8
2.5 < x
Find a \( a \) so that:
\( 0 < 8a+4 ≤ -a+9 \)
which value of X satisfies:
\( 8x< 3x+9 \)
but does not exist in:
\( 5x+4<0 \)
\( 5a+14 < -2x < 3a+8 \)Calculate X in terms of \( a \)
given that \( 0 < a \).
Find a so that:
0 < 8a+4 ≤ -a+9
-\frac{1}{2} < a ≤ \frac{5}{9}
which value of X satisfies:
8x< 3x+9
but does not exist in:
5x+4<0
-0.8 ≤ x < 1.8
5a+14 < -2x < 3a+8 Calculate X in terms of
given that 0 < a .
No solution