Examples with solutions for Factoring Trinomials: Using short multiplication formulas

Exercise #1

Below is a rectangle.

x>0

The area of the rectangle is x213 x^2-13 .

Calculate x.

x-4x-4x-4x+1x+1x+1

Video Solution

Step-by-Step Solution

First, let's recall the formula for calculating the area of a rectangle with sides of length a,b (length units):

S=ab S_{\boxed{\hspace{8pt}}}=a\cdot b

Therefore, by direct calculation, for the rectangle shown in the drawing with side lengths:

x+1,x4 x+1,\hspace{6pt}x-4 (length units),

The expression for the area is:

S=(x+1)(x4) S_{\boxed{\hspace{8pt}}}=(x+1)(x-4)

However, from the given information, we know that the expression for the area of the rectangle in the drawing is:

S=x213 S_{\boxed{\hspace{8pt}}}=x^2-13

Therefore, we can conclude the existence of the equation:

(x+1)(x4)=x213 (x+1)(x-4)=x^2-13

Now, in order to simplify the equation, let's recall the expanded distribution law:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd

Let's continue and solve the equation we got. First, we'll open the parentheses on the left side, then we'll move terms and combine like terms, and solve the simple equation that results:

(x+1)(x4)=x213x24x+x4=x2133x=10/:(-3)x=3 (x+1)(x-4)=x^2-13 \\ x^2-4x+x-4=x^2-13\\ -3x=-10\hspace{9pt}\text{/:(-3)}\\ \boxed{x=3} (length units),

Note- this solution for the unknown does not contradict the domain of definition (where the side lengths must be positive, as required) and the area obtained by substituting it into the given expression for the area in the problem:

S=x213S=5213=2513=12 S_{\boxed{\hspace{8pt}}}=x^2-13 \\ \downarrow\\ S_{\boxed{\hspace{8pt}}}=5^2-13 =25-13=\boxed{12} (area units)

Indeed positive, as expected.

Therefore, the correct answer is answer C.

Answer

x=3 x=3

Exercise #2

Choose the expression that represents the area of the square below.

x+1x+1x+1

Video Solution

Step-by-Step Solution

First, let's recall the formula for calculating the area of a square with side length y (length units):

S=y2 S_{\boxed{}}=y^2 Therefore, for a square with side length:

x+1 x+1 (length units), the expression for the area is:

S=(x+1)2 S_{\boxed{}}=(x+1)^2 Now, in order to simplify the expression, let's recall the perfect square binomial formula:

(a±b)2=a2±2ab+b2 (a\pm b)^2=a^2\pm2ab+b^2 Let's continue and apply this formula to the area expression we got:

S=(x+1)2S=x2+2x1+1S=x2+2x+1 S_{\boxed{}}=(x+1)^2 \\ \downarrow\\ S_{\boxed{}}=x^2+2\cdot x\cdot 1+1\\ \boxed{ S_{\boxed{}}=x^2+2x+1}\\ This is the most simplified expression for the given square's area,

therefore the correct answer is answer D.

Answer

x2+2x+1 x^2+2x+1

Exercise #3

Look at the triangle below.

Calculate x given that x>0 .

x+1x+1x+1xxxx+2x+2x+2

Video Solution

Answer

x=3 x=3

Exercise #4

The area of the triangle is x22 \frac{x^2}{2} .

Calculate x.

XXXX-1X-1X-1X+2X+2X+2

Video Solution

Answer

x=2 x=2

Exercise #5

The square shown below has an area of 36.

x>0

Calculate x.

x+1x+1x+1

Video Solution

Answer

x=5 x=5

Exercise #6

Calculate x given that x>0 .

xxxx+7x+7x+7131313

Video Solution

Answer

x=5 x=5

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