Congruent Rectangles: Identifying Congruent Rectangles

Examples with solutions for Congruent Rectangles: Identifying Congruent Rectangles

Exercise #1

Are the rectangles below congruent?

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Video Solution

Step-by-Step Solution

Since there are two pairs of sides that are equal, they also have the same area:

8×4=32 8\times4=32

Therefore, the rectangles are congruent.

Answer

Yes

Exercise #2

Are the rectangles below congruent?

222333444333

Video Solution

Step-by-Step Solution

We can see that the length is identical in both rectangles: 3=3.

However their widths are not equal, as one is 2 while the other is 4.

Therefore, the rectangles are not congruent.

Answer

No

Exercise #3

Are the rectangles congruent?

222555444AAABBBDDDCCCEEEGGG

Video Solution

Step-by-Step Solution

Note that DC divides AE into two unequal parts.

AC=5 while CE=4

The area of rectangle ABDC is equal to:

5×2=10 5\times2=10

The area of rectangle CDGE is equal to:

4×2=8 4\times2=8

Therefore, the rectangles do not overlap.

Answer

No

Exercise #4

The perimeter of A is 20 cm.

The perimeter of B is also 20 cm.

The area of them is identical.

Are the rectangles congruent?

P=18P=18P=18P=18P=18P=18ab

Step-by-Step Solution

To determine if the two rectangles are congruent, we start by understanding that two rectangles are congruent if they have identical lengths and widths. In this problem, both rectangles have a perimeter of 20 cm and identical areas, which suggests they could potentially be congruent.

Let's recall the formulas:
Perimeter of a rectangle: P=2(l+w) P = 2(l + w)
Area of a rectangle: A=l×w A = l \times w

Given that each rectangle has a perimeter P=20 P = 20 , we can write:
2(lA+wA)=20 2(l_A + w_A) = 20 for Rectangle A,
2(lB+wB)=20 2(l_B + w_B) = 20 for Rectangle B,
which simplifies to:
lA+wA=10 l_A + w_A = 10 ,
lB+wB=10 l_B + w_B = 10 .

The identical area condition gives us:
lA×wA=lB×wB l_A \times w_A = l_B \times w_B .

Given that both the sums of l l and w w (using perimeter) and their products (using area) are equal, this enforces that lA=lB l_A = l_B and wA=wB w_A = w_B .

This implies that the rectangles are congruent (i.e., have identical lengths and widths).

Therefore, the solution to the problem is Yes.

Answer

Yes

Exercise #5

Are the rectangles congruent?

A=20A=20A=20A=24A=24A=24

Video Solution

Answer

No