Standard Form of the Quadratic Function

🏆Practice standard representation

Standard Form of the Quadratic Function

The standard form of the quadratic function is:
Y=ax2+bx+cY=ax^2+bx+c

For example:
Y=4x2+3x+15Y=4x^2+3x+15

Start practice

Test yourself on standard representation!

Create an algebraic expression based on the following parameters:

\( a=3,b=6,c=9 \)

Practice more now

How do you go from standard form to vertex form?

  • We need to find the vertex of the parabola using the formula to find the XX vertex.
  • Let's find the YY vertex.
  • Let's place in the vertex form template the X X vertex instead of PP, the YY vertex instead of CC and the aa instead of aa.

How do you go from standard form to factored form?

  • Let's find the points of intersection of the parabola with the xx axis.
  • Let's place it in the factored form template.

Look!
If we were to realize that in the standard form there is a coefficient for X2X^2 we will place it in the factoring formula before locating the intersection points there, as follows:

y=a×(xt)×(xk) y=a\times(x-t)\times(x-k)


Examples and exercises with solutions of the Standard form of the quadratic function

Exercise #1

Create an algebraic expression based on the following parameters:

a=3,b=6,c=9 a=3,b=6,c=9

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the given parameters a=3 a = 3 , b=6 b = 6 , c=9 c = 9 .
  • Step 2: Use the standard formula for a quadratic expression, which is y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Substitute the given values into this formula.

Now, let's work through each step:
Step 1: We have the parameters a=3 a = 3 , b=6 b = 6 , c=9 c = 9 .
Step 2: The standard form of a quadratic equation is y=ax2+bx+c y = ax^2 + bx + c .
Step 3: Substituting the given values into the expression, we get:

y=3x2+6x+9 y = 3x^2 + 6x + 9

Therefore, the algebraic expression based on the given parameters is:

3x2+6x+9 3x^2 + 6x + 9 .

Answer

3x2+6x+9 3x^2+6x+9

Exercise #2

Create an algebraic expression based on the following parameters:

a=12,b=12,c=12 a=\frac{1}{2},b=\frac{1}{2},c=\frac{1}{2}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify and substitute the values of a a , b b , and c c into the equation y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Simplify the equation to obtain the required expression.
  • Step 3: Compare the simplified expression with the provided multiple-choice answers.

Let's work through each step:

Step 1: The given coefficients are a=12 a = \frac{1}{2} , b=12 b = \frac{1}{2} , and c=12 c = \frac{1}{2} . Substitute these values into the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c :

y=12x2+12x+12 y = \frac{1}{2}x^2 + \frac{1}{2}x + \frac{1}{2}

Step 2: The expression is already simplified. The coefficients are correctly substituted, and no further simplification is needed:

y=x22+x2+12 y = \frac{x^2}{2} + \frac{x}{2} + \frac{1}{2}

Step 3: Compare this expression to the provided multiple-choice options. The correct match is:

Choice 1: x22+x2+12 \frac{x^2}{2} + \frac{x}{2} + \frac{1}{2}

Therefore, the algebraic expression is x22+x2+12 \frac{x^2}{2} + \frac{x}{2} + \frac{1}{2} .

Answer

x22+x2+12 \frac{x^2}{2}+\frac{x}{2}+\frac{1}{2}

Exercise #3

Create an algebraic expression based on the following parameters:

a=2,b=12,c=4 a=2,b=\frac{1}{2},c=4

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow the steps outlined:

  • Step 1: Identify the given values for the quadratic function's parameters: a=2 a = 2 , b=12 b = \frac{1}{2} , and c=4 c = 4 .
  • Step 2: Apply these values to the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Substitute the values to construct the algebraic expression.

Now, let's proceed with these steps:

Given the standard form of a quadratic expression y=ax2+bx+c y = ax^2 + bx + c :

Substituting the values, we obtain:

y=2x2+12x+4 y = 2x^2 + \frac{1}{2}x + 4

Therefore, the correct algebraic expression for the quadratic function is 2x2+12x+4 2x^2 + \frac{1}{2}x + 4 .

Answer

2x2+12x+4 2x^2+\frac{1}{2}x+4

Exercise #4

Create an algebraic expression based on the following parameters:

a=2,b=2,c=2 a=2,b=2,c=2

Video Solution

Step-by-Step Solution

To solve this problem, we need to create a quadratic expression using the provided values for a a , b b , and c c .

The standard form of a quadratic function is:

y=ax2+bx+c y = ax^2 + bx + c

Given the values:

  • a=2 a = 2
  • b=2 b = 2
  • c=2 c = 2

We substitute these values into the standard quadratic formula:

y=2x2+2x+2 y = 2x^2 + 2x + 2

Therefore, the algebraic expression for the quadratic function based on the provided parameters is 2x2+2x+2 2x^2 + 2x + 2 .

The correct answer is choice 1: 2x2+2x+2 2x^2 + 2x + 2 .

Answer

2x2+2x+2 2x^2+2x+2

Exercise #5

Choose the correct algebraic expression based on the parameters:

a=3,b=3,c=7 a=-3,b=3,c=7

Video Solution

Step-by-Step Solution

To solve this problem, we will substitute the given values into the standard quadratic form:

  • Step 1: Identify the formula to use. We need the standard form of a quadratic function, which is y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Substitute the given parameters into the formula:
    a=3 a = -3 , b=3 b = 3 , and c=7 c = 7 .
  • Step 3: Perform the substitution:
    Substituting in, we get y=3x2+3x+7 y = -3x^2 + 3x + 7 .

Therefore, the correct algebraic expression is 3x2+3x+7 -3x^2 + 3x + 7 .

This corresponds to choice 2 of the multiple-choice options provided.

Answer

3x2+3x+7 -3x^2+3x+7

Join Over 30,000 Students Excelling in Math!
Endless Practice, Expert Guidance - Elevate Your Math Skills Today
Test your knowledge
Start practice