Standard Form of the Quadratic Function

🏆Practice standard representation

Standard Form of the Quadratic Function

The standard form of the quadratic function is:
Y=ax2+bx+cY=ax^2+bx+c

For example:
Y=4x2+3x+15Y=4x^2+3x+15

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Test yourself on standard representation!

Choose the correct algebraic expression based on the parameters:

\( a=-3,b=3,c=7 \)

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How do you go from standard form to vertex form?

  • We need to find the vertex of the parabola using the formula to find the XX vertex.
  • Let's find the YY vertex.
  • Let's place in the vertex form template the X X vertex instead of PP, the YY vertex instead of CC and the aa instead of aa.

How do you go from standard form to factored form?

  • Let's find the points of intersection of the parabola with the xx axis.
  • Let's place it in the factored form template.

Look!
If we were to realize that in the standard form there is a coefficient for X2X^2 we will place it in the factoring formula before locating the intersection points there, as follows:

y=a×(xt)×(xk) y=a\times(x-t)\times(x-k)


Examples and exercises with solutions of the Standard form of the quadratic function

Exercise #1

Choose the correct algebraic expression based on the parameters:

a=3,b=3,c=7 a=-3,b=3,c=7

Video Solution

Step-by-Step Solution

To solve this problem, we will substitute the given values into the standard quadratic form:

  • Step 1: Identify the formula to use. We need the standard form of a quadratic function, which is y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Substitute the given parameters into the formula:
    a=3 a = -3 , b=3 b = 3 , and c=7 c = 7 .
  • Step 3: Perform the substitution:
    Substituting in, we get y=3x2+3x+7 y = -3x^2 + 3x + 7 .

Therefore, the correct algebraic expression is 3x2+3x+7 -3x^2 + 3x + 7 .

This corresponds to choice 2 of the multiple-choice options provided.

Answer

3x2+3x+7 -3x^2+3x+7

Exercise #2

Create an algebraic expression based on the following parameters:

a=0,b=1,c=0 a=0,b=1,c=0

Video Solution

Step-by-Step Solution

To solve this problem, we'll use the following steps:

  • Step 1: Substitute a=0 a = 0 , b=1 b = 1 , c=0 c = 0 into the quadratic equation y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Simplify the expression based on these substitutions.

Working through these steps:

Step 1: Start with the expression y=ax2+bx+c y = ax^2 + bx + c .

Since a=0 a = 0 , then ax2=0x2=0 ax^2 = 0 \cdot x^2 = 0 .
Since b=1 b = 1 , then bx=1x=x bx = 1 \cdot x = x .
Since c=0 c = 0 , then c=0 c = 0 .

Step 2: Plug these values into the equation:

The expression simplifies to:

y=0+x+0 y = 0 + x + 0

Thus, the simplified algebraic expression is y=x y = x .

Therefore, the solution to the problem is x x .

Answer

x x

Exercise #3

Create an algebraic expression based on the following parameters:

a=1,b=0,c=0 a=-1,b=0,c=0

Video Solution

Step-by-Step Solution

We begin by noting that the general form of a quadratic function is represented by the equation:

y=ax2+bx+c y = ax^2 + bx + c

Given the parameters a=1 a = -1 , b=0 b = 0 , and c=0 c = 0 , we substitute these values into the equation:

y=(1)x2+(0)x+0 y = (-1)x^2 + (0)x + 0

Simplifying the expression, we get:

y=x2 y = -x^2

Thus, the algebraic expression representing the given parameters is x2 -x^2 .

The correct answer choice that corresponds to this expression is:

x2 -x^2

Answer

x2 -x^2

Exercise #4

Create an algebraic expression based on the following parameters:

a=1,b=16,c=64 a=1,b=16,c=64

Video Solution

Step-by-Step Solution

To solve this problem, let's proceed with the construction of the quadratic expression:

  • Step 1: Recognize the standard form of a quadratic expression, which is ax2+bx+c ax^2 + bx + c .
  • Step 2: Substitute the given values into this formula:
    • a=1 a = 1
    • b=16 b = 16
    • c=64 c = 64
    Plugging in these values, we determine the expression to be 1x2+16x+64 1x^2 + 16x + 64 , which simplifies to x2+16x+64 x^2 + 16x + 64 .

Thus, the algebraic expression we derive from these parameters is the quadratic expression:

x2+16x+64 x^2 + 16x + 64

This matches the correct choice provided in the given multiple-choice options.

Answer

x2+16x+64 x^2+16x+64

Exercise #5

Create an algebraic expression based on the following parameters:

a=1,b=1,c=0 a=-1,b=1,c=0

Video Solution

Step-by-Step Solution

To determine the algebraic expression, we start with the standard quadratic function:

y=ax2+bx+c y = ax^2 + bx + c

Given the values:

  • a=1 a = -1
  • b=1 b = 1
  • c=0 c = 0

We substitute these into the formula:

y=(1)x2+1x+0 y = (-1)x^2 + 1x + 0

Simplifying the expression gives:

y=x2+x y = -x^2 + x

Thus, the algebraic expression, when these parameters are substituted, is:

The solution to the problem is x2+x \boxed{-x^2 + x} .

Answer

x2+x -x^2+x

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